Question 1 Sample with size n 100 has mean 30 Assuming the
Question 1
Sample with size n = 100 has mean = 30.
Assuming the population standard deviation is 8,
construct 95% confidence interval for population mean.
Use formula on page 312, z?/2 = 1.96
between 28.4 and 31.6
between 27.0 and 33.0
between 26.1 and 34.2
between 24.1 and 35.9
1 points
Question 2
With sample mean x = 12.5, sample size n = 40
and population standard deviation = 4
find 99% confidence interval for population mean.
Use formula on page 312 with z?/2 = 2.575
between 11.5 and 13.5
between 10.9 and 14.1
between 10.1 and 15.1
between 7.4 and 14.2
1 points
Question 3
Use Appendix Table IV to find t0.10 for sample size n = 16.
Remember, df in the table is: df = n ? 1
2.015
1.860
1.725
1.341
1 points
Question 4
For sample mean x = 150, sample size n = 36
and sample standard deviation s = 40
find 80% confidence interval for population mean.
Population standard deviation is not known,
you should use formula on page 328 with t-value
from Appendix Table IV (use column t0.10).
135.6 to 148.4
154.2 to 175.8
141.3 to 158.7
162.3 to 187.5
1 points
Question 5
Use example posted in this week Lectures section
to estimate Population Proportion.
Sample proportion is ps = 0.48, sample size 125,
zc = 1.96 (90% confidence level).
0.26 to 0.64
0.39 to 0.57
0.41 to 0.52
0.28 to 0.71
| between 28.4 and 31.6 | ||
| between 27.0 and 33.0 | ||
| between 26.1 and 34.2 | ||
| between 24.1 and 35.9 |
Solution
1) between 28.4 and 31.6
2) b) between 10.9 and 14.1
3) 1.341
4) 141.3 to 158.7
5) 0.41 to 0.52

