dydt 3ty6t y04 ySolutiondy201y3tdt integrate now ln201y013t2
dy/dt+ .3ty=6t
y(0)=4
y=?
y(0)=4
y=?
Solution
dy/(2-0.1*y)=3tdt
integrate now
ln(2-0.1*y)/(-0.1)=(3t^2)/2 +c
substitute y(0)=4
then , we c=-10ln(1.6)
after rearranging
ln(16/(20-y))=0.15t^2
=> y=20-16*e^(-0.15t^2)

