The following sample observations were randomly selected Do

The following sample observations were randomly selected. (Do not round the intermediate values. Round your answers to 2 decimal places.) Determine the 0.95 confidence interval for the mean predicted when Determine the 0.95 prediction interval for an individual predicted when

Solution

Regression Analysis

r²

0.705

n

5

r

0.840

k

1

Std. Error

4.342

Dep. Var.

y

ANOVA table

Source

SS

df

MS

F

p-value

Regression

135.3212

1  

135.3212

7.18

.0751

Residual

56.5668

3  

18.8556

Total

191.8880

4  

Regression output

confidence interval

variables

coefficients

std. error

   t (df=3)

p-value

95% lower

95% upper

Intercept

0.4247

4.9012

0.087

.9364

-15.1731

16.0224

x

2.1527

0.8036

2.679

.0751

-0.4046

4.7101

Predicted values for: y

95% Confidence Interval

95% Prediction Interval

x

Predicted

lower

upper

lower

upper

Leverage

7

15.4938

8.35

22.64

-0.06

31.05

0.267

95% confidence interval =(8.35, 22.64)

95% Prediction interval =(-0.06, 31.05)

Regression Analysis
	r²	0.705	n	5
	r	0.840	k	1
	Std. Error	4.342	Dep. Var.	y
ANOVA table
Source	SS	df	MS	F	p-value
Regression	135.3212	1	135.3212	7.18	.0751
Residual	56.5668	3	18.8556
Total	191.8880	4
Regression output				confidence interval
variables	coefficients	std. error	t (df=3)	p-value	95% lower	95% upper
Intercept	0.4247	4.9012	0.087	.9364	-15.1731	16.0224
x	2.1527	0.8036	2.679	.0751	-0.4046	4.7101
Predicted values for: y
		95% Confidence Interval	95% Prediction Interval
x	Predicted	lower	upper	lower	upper	Leverage
7	15.4938	8.35	22.64	-0.06	31.05	0.267