Write a C program that reads ten integers The program should
     Write a C program that reads ten integers. The program should count and print on the screen total number of odd and even values among these ten inputs. 
  
  Solution
#include <stdio.h>
 
 void main()
 {
 int a[10], i, n,count=0,count1=0;
 
 printf(\"Enter the size of an array \ \");
 scanf(\"%d\", &n);
 printf(\"Enter the elements of the array \ \");
 for (i = 0; i < n; i++)
 {
 scanf(\"%d\", &a[i]);
 }
 printf(\"Number of Even Numbers : \");
 for (i = 0; i < n; i++)
 {
 if (a[i] % 2 == 0)
 {
 count++;
 }
 else
 {
 count1++;
 }
 }
 printf(\"%d \\t\", count);
 printf(\"\  Number of odd numbers :\");
 printf(\"%d \\t\", count1);
 }
If you want to check for 10 integers simply give the value of n as 10 or if you want to give more numbers change the value of n.

