The number os lamps a company sells is a function Nx 20050x3
The number os lamps a company sells is a function N(x)= 200+50x+36.5x^2-x^3, where x is the price charged for each lamp and 0 <= x <= 37. The price to maximize the number of lamps sold should be....
Solution
dN(x)/dx = 50 + 73x - 3x2 = 0
x = 25, -0.67
0<=x<=37 hence x = 25
