Perform a chisquare homogeneity test An independent simple r

Perform a chi-square homogeneity test. An independent simple random sample of residents in three regions gave the data on race shown in the table. At the 1% significance level, do the data provide sufficient evidence to conclude that a difference exists in race distributions among the three regions? The racial distribution is not the same in at least two of the three regions. H_a: The racial distribution is the same in at least two of the three regions. The racial distribution is not the same in each of the three regions. The racial distribution is the same in each of the three regions. Find the test statistic Find the critical value. Reject Ho. The data do not provide sufficient evidence that there is a difference. Reject Ho. The data provide sufficient evidence that there is a difference Do not reject H_0. The data do not provide sufficient evidence that there is a difference Do not reject The data provide sufficient evidence that there is a difference. At least one assumption is violated. Therefore, the test cannot be conducted.

Solution

a.

we know ⁿP_r = n!/(n-r))!

¹¹P₅ = 11!/6! = 55440

b.

ⁿC_r = n!/[(n-r)!r!]

¹¹C₅ = 11!/[6!*5!] =462