A ball is thrown from a roof the equation is st 16tsquared50

A ball is thrown from a roof the equation is s(t)= -16t(squared)+50+120.

What is the maximumum height the ball will reach, and at what time will it reach that height.

Please show graph with xmin and ymin changes also what do i inoput into calculaotr
y1=
y2=

Solution

The equation of the trajectory of a ball is thrown from a roof is s(t)= - 16t² +50t +120, where s(t) is the height t units of time after the ball is thrown.

There are 3 methods of answering the question.