A coin is slightly bent and as a result the probability of a

A coin is slightly bent and as a result the probability of a head is p=.55. Suppose that you toss the coin 10 times. Use binomial distribution to find the probability of getting 7 or more heads.

A coin is slightly bent and as a result the probability of a head is p=.55. Suppose that you toss the coin 10 times. Use binomial distribution to find the probability of getting 7 or more heads.

Solution

given

probability of head =0.55

then probability of tell=0.45

X denote number of heads

Y denotes number of tails

then we have to find P(X>7)

this means probability of tails at most 3

then P(X>7)=P(Y<3)

then

P(X>7)=P(Y<3)=P(Y=0)+P(Y=1)+P(Y=2)+P(Y=3)

then from given above table

we get

P(X>7)=P(Y<3)=0.0025+0.0207+0.0763+0.1665=0.266 answer