M4i9 14 You Pathways lMathAS Assess e Chegg Study I Guided S
M4i9 #14
You Pathways lMathAS Assess e Chegg Study I Guided So × -> ahttps://imathas.rationalreasoning.net/assessment/showtest.php?action-skip&to;=13&reattempt;=13 For quick access, place your bookmarks here on the bookmarks bar. Import bookmarks now... a @ Home > Murdock Precalc 013> Assessment Jeremee Hemphill M4 I9 Homework Due in 7 hours, 11 minutes. Due Wed 04/27/2016 11:59 pm Show Intro/Instructions Questions Suppose j is an exponential function. Use the table below to answer the following questions 6 Q2[44] j(f) 9 20.25 45.5625 102.515625 Q4 [3/3] a. Evaluate j(0) Preview b. What is the 1-unit growth factor? Q8[44] Preview Q 10 [1/1] Q 11 [3/3] C Q 12 (1/5) C Q13 (2/3) C Q 14 (0/3) C Q 15 (0/3) C Q 16 (0/3) Q17 (0/6) C Q 18 (0/4) Q19 [1/1] c. Evaluate j (187) Preview : 3 License Points possible Unlimited attempts Score on last attempt: 0. Score in gradebook: 0 Post this question to forum Submit Grade: 39/63 Print Version 4:48 PM l\')-all 4/27/2016Solution
Solution:
Let the exponential function be j(f) = ab^f
Given f = 2, then j(f) =9 and f = 4, then j(f) = 20.25.
Thus ab^2 = 9 ...(i) and ab^4 = 20.25 ...(ii).
Dividing equation (ii) by (i), we get
b^2 =20.25/9 =2.25
or b = 1.5
Now from equation ( i), we have a(1.5)^2 = 9 or a(2.25) = 9 or a = 4.
Thus the fuction become j(f) = 4*(1.5)^f
a. Therefore j(0) =4*(1.5)^0 = 4*(1)
j(0) = 4 Ans.
b. To know the groth, we have j(0) = 4 , and j(1) = 4(1.5) = 6.
Thus for unit change in f the function value increase by 6-4 = 2 unit.
Therefore 1-unit growth factor is 2. Ans.
c. We know that j(f) = 4*(1.5)^f => f = j^-1 (4*(1.5)^f)
Given 4*(1.5)^f = 187
or (1.5)^f = 46.75
or f log (1.5) = log (46.75)
Thus f = log (46.75)/log (1.5)
or f = 9.48
Therefore j^-1(187) = 9.48 Ans.
