Given the three simple events that form the sample space det

Given the three simple events that form the sample space, determine which of the following cannot be a probability.

P(E1)=0.502, P(E2)=-0.037, P(E3)=0.536

P(E1)=1.100, P(E2)=-0.300, P(E3)=0.200

P(E1)=0, P(E2)=0.75, P(E3)=0.25

P(E1)=0.369, P(E2)=0.244, P(E3)=0.387

Given the three simple events that form the sample space, determine which of the following cannot be a probability

P(E1)=0.5, P(E2)=0.1, P(E3)=0.6

P(E1)=1, P(E2)=0, P(E3)=0

P(E1)=0.3, P(E2)=0, P(E3)=0.7

P(E1)=0.1, P(E2)=0.1, P(E3)=0.8

Solution

I.

P(E1)=1.100, P(E2)=-0.300, P(E3)=0.200

Probability any event can\'t be more than one

II.

P(E1)=0.5, P(E2)=0.1, P(E3)=0.6

Sum of all possibble events should be equals to one. P(E1)+P(E2)+P(E3)= 1.2 > 1