A and B are events with PA034 and PB055 Find Probabilities a

A and B are events with P(A)=0.34 and P(B)=0.55

Find Probabilities are (AnB=A and AUB=B)

a.) P(AnB)

b.)P(AUB)

c.)P(A n not B)

Solution

P(A)=0.34   P(B)=0.55

a) P (A intersection B) = P(A)*P(B) = 0.187
b) P (A U B) = P(A)+P(B)-P(A)P(B) = 0.703
c) P (A I B) = P(AnB)/P(B) = P(A)= 0.34