1 pt Suppose 0Solution1 Log A log A log B 0 log BA log

(1 pt) Suppose 0

1. Log A < log A + log B < 0 < log (B^A) < log B

u = log₁₀ 2 , v = log₁₀ 5 ;

log₁₀ (0.4) = log₁₀ (2² / 2 *5) = log₁₀ ( 2)² – log₁₀ ( 2*5) = 2log₁₀ 2 – (log₁₀ 2 + log₁₀ 5) = 2u – ( u + v) = u – v

log₁₀ 0.025 = log₁₀ ( 2^-3 * 5^-1) = -3 log₁₀ 2 – log₁₀ 5 = -3u – v = - (3u + v)

log₁₀ 80 = log₁₀ ( 2⁴ * 5) = 4log₁₀ 2 + log₁₀ 5 = 4u + 5

log₁₀ 10 = log₁₀ ( 2^1/2 * 5^1/2) = ½ log₁₀ 2 + ½ log₁₀ 5 = ½ u + ½ v = ½ (u + v)