Problem 2 The two trains travel on separate tracks one circu
     Problem 2: The two trains travel on separate tracks, one circular and one straight. The train on the circular track is traveling at a constant speed of 50 ft/s, while the train on the straight track is traveling at a speed of 20 ft/s and its speed is increasing at a rate of 2ft/s2. What is the velocity of passenger A as observed by passenger B (i.e., in coordinate system fixed to the train car that passenger B is in)? 500 ft 50 ftls 20 ftls  
  
  Solution
vel of A = 20 ft/s
acceleration a = 2 ft/s2
distance travelled at any instant by A = s= ut + 0.5 * a * t2
= 20t + t2
angular vel of B = w = v / r
= 0.1 rad/s
By taking the centre of circle as reference
rb = 500 (sin (wt) i + cos (wt) j )
ra = 1000 i + (20t + t2) (-j)
= 1000 i - ( 20t + t2 ) j
rb - ra = (500sin wt + 1000) i +( 500cos wt -(20t + t2)) j
differentiating this gives velocity
vb - va = (50cos wt) i + (-50sin wt - (20 + 2t)) j
= ( 50 cos wt) i - ( 50sin wt + (20 + 2t)) j
rel velocity changes at every instant..it can be found at particular instant at time t in above eq.

