I do not know how to solve this Please Help me On May 23 201
I do not know how to solve this, Please Help me. On May 23, 2013, Gallup reported that of the 1,005 people surveyed, 76% of U.S. workers believe that they will continue working past retirement age. The confidence level for this study was reported at 95% with a ±3% margin of error. a. Determine the estimated proportion from the sample. b. Determine the sample size. c. Identify CL and . d. Calculate the error bound based on the information provided. e. Compare the error bound in part d to the margin of error reported by Gallup. Explain any differences between the values. f. Create a confidence interval for the results of this study. g. A reporter is covering the release of this study for a local news station. How should she explain the confidence interval to her audience?
Solution
a)
0.76
b)
1.96 ----------- alpha/2 = 0.025----------------Z=1.96
sample size = 1.96^2 * 0.76 * 0.24 / (0.03)^2
sample size = 0.70070784 / 0.03^2
sample size = 778.56
c)
CL = 0.76
alpha = 1 - 0.95 = 0.05
d)
error = 0.03
for the other literals I can gladly help you but you should post it in a new question
