I do not know how to solve this Please Help me On May 23 201

I do not know how to solve this, Please Help me. On May 23, 2013, Gallup reported that of the 1,005 people surveyed, 76% of U.S. workers believe that they will continue working past retirement age. The confidence level for this study was reported at 95% with a ±3% margin of error. a. Determine the estimated proportion from the sample. b. Determine the sample size. c. Identify CL and . d. Calculate the error bound based on the information provided. e. Compare the error bound in part d to the margin of error reported by Gallup. Explain any differences between the values. f. Create a confidence interval for the results of this study. g. A reporter is covering the release of this study for a local news station. How should she explain the confidence interval to her audience?

Solution

a)

0.76

b)

1.96 -----------   alpha/2 = 0.025----------------Z=1.96

sample size = 1.96^2 * 0.76 * 0.24 / (0.03)^2

sample size = 0.70070784 /   0.03^2

sample size = 778.56

c)

CL = 0.76

alpha = 1 - 0.95 = 0.05

d)

error = 0.03

for the other literals I can gladly help you but you should post it in a new question

I do not know how to solve this, Please Help me. On May 23, 2013, Gallup reported that of the 1,005 people surveyed, 76% of U.S. workers believe that they will

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