The weight of cans of fruit is normally distributed with a m

The weight of cans of fruit is normally distributed with a mean of 1,054 grams and a standard deviation of 58 grams. What percent of the cans weigh 852 grams or less?

0.0002

0.0124

0.089

0.0217

Solution

Normal Distribution
Mean ( u ) =1054
Standard Deviation ( sd )=58
Normal Distribution = Z= X- u / sd ~ N(0,1)                  
a)
P(X > 852) = (852-1054)/58
= -202/58 = -3.4828
= P ( Z >-3.483) From Standard Normal Table
= 0.9998                  
P(X < = 852) = (1 - P(X > 852)
= 1 - 0.9998 = 0.0002