What is the 975th percentile of a normal distribution with m

What is the 97.5th percentile of a normal distribution with mean = 10 and standard deviation = 4?

19.60

15.12

17.84

16.58

1 points

Solution

First, we get the z score from the given left tailed area. As          
          
Left tailed area =    0.975      
          
Then, using table or technology,          
          
z =    1.959963985      
          
As x = u + z * s,          
          
where          
          
u = mean =    10      
z = the critical z score =    1.959963985      
s = standard deviation =    4      
          
Then          
          
x = critical value =    17.83985594 = 17.84 [answer, c]