num 0 for I 1 I Solutionthe output is 20 explanation fori0

Solution

the output is 20

explanation:

for(i=0;i<=3;i++)
{
num=num+2;
for(j=1;j<=3;j++)
{
num=num+1;
}
}

when i=0 num=2 then it runs for j=1 2 and 3 and num increases 1 by each time.

Hence num becomes 5

when i=1 num=7 then it runs for j=1 2 and 3 and num increases 1 by each time.

Hence num becomes 10

when i=2 num=12 then it runs for j=1 2 and 3 and num increases 1 by each time.

Hence num becomes 15

when i=3 num=17 then it runs for j=1 2 and 3 and num increases 1 by each time.

Hence num becomes 20

Then it exists the loop