If water is at a pressure of 40 MPa and a temperature of 320

If water is at a pressure of 4.0 MPa and a temperature of 320degree C, what are the corresponding values of v, u, h and s?

Solution

>> At Pressure, P = 4 MPa,

Saturation Temperature, T < 320 C

>> So, State is Superheated Steam

>> So, Using Steam Table at this state,

v = Specific Volume = 0.062 m³/Kg

u = Specific Internal Energy = 2768.192 KJ/Kg

h = Specific Enthalpy = 3016.276 KJ/Kg

s = Specific Entropy = 6.4575 KJ/Kg-K