Find the area of the triangle having the indicated angle and

Find the area of the triangle having the indicated angle and sides () Use the Last of Since to solve (of possible) the triangle. If two solution exist, find both. (If a triangle is not possible enter IMPOSSIBLE in each corresponding answer blank.) A = 100 a = 125 b = 220 Find the area of the triangle having the indicated angle and sides. ().

Solution

Area of triangle=(ab/2)sinC

a=7 ,b=8,C=120

Area=(7*8/2)sin120= 28 sin120= 24.2cm

Second question

A=100 degree

a=125   b=220

SinA/a=sinB/b

sin100/125=sinB/220

sinB=1.73

Here the value of sin theta is more then 1 and sin theta always lies in [-1,1]. So it is not possible

Next question

A=47degree30 \'=47.5 degree

b=57

c= 74

Area= (bc/2)sinA = (57*74/2)sin47.5= 1554.9