The regression equation is reported as y2142x6178 and the r2

The regression equation is reported as

y=21.42x+61.78

and the r2=0.36.

What is the correlation coefficient for this data set?
r =

y=2.057x+45.151

with a correlation coefficient of r=0.748 (which is significant at =0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 120 on the response variable.

What is the predicted explanatory value?
x =

y=3.572x61.153

with a correlation coefficient of r=0.654. You want to predict what value (on average) for the response variable will be obtained from a value of 140 as the explanatory variable.

What is the predicted response value?
y =

y=1.658x0.913

with a correlation coefficient of r=0.666. You want to predict what value (on average) for the response variable will be obtained from a value of 100 as the explanatory variable.

What is the predicted response value?
y =

(Report answer accurate to one decimal place.)

Solution

What is the correlation coefficient for this data set?

r= srqt (0.36) = 6

R = -6 is negative because if you graph the equation of regression it has a negative slope

What is the predicted explanatory value?

y=2.057x45.151

120= 2.057X - 45.151

X = 36.4

What is the predicted response value?

y=3.572x61.153

Y = 3.572*140 - 61.153

Y= 438.9

What is the predicted response value?

y=1.658x0.913

Y = -1.658*100 - 0.913

Y= -166.7