Michael purchased a certain number of shares of one stock fo
Solution
Let, x be cost of first stock\'s share
SO number of shres of first stock bought =1287/x
Second stock costs: x-6
So number of shares of second stock that can be bought =1287/(x-6)
So,
1287/x+6=1287/(x-6)
1287(x-6)+6x(x-6)=1287x
6x^2-36x-1287*6=0
x^2-6x-1287=0
1287=429*3=143*9=13*11*9=39*33
x^2-39x+33x-1287=0
x(x-39)+33(x-39)
=0
x=39
So first share costs 39 and second share costs 33
Number of shares of first stock purchased=1287/39=33
