Jupiter please do it correctly and show result The speeding
Solution
// program is in C language.
// program for implementing speeding fine based on given requirements. fine =60 and for every 1 mph = $ 5.00 if construction violated(\'y\') fine doubled and
 // speed over 90 gets further 250 extra fine.
// including libraries
 #include<stdio.h>
//declaration of test and speeding functions.
 void test();
 int speeding(int , int ,char );
 int main(){
    test();                            // calling test function.
 }
 // speeding functin definition.
 int speeding(int sl, int cs,char c_l){
    int value = 0;
    if(sl<cs){                       // if clock speed crosses speeding limit.
        value=60+(cs-sl)*5;              
        if(c_l==\'Y\' || c_l == \'y\'){ // if construction violation occurs.
            value=value*2;
        }
        if(cs>90){                   // if clock speed over 90
            value=value+250;
        }
    }
    return value;                    // speeding function returns value never prints.
 }
 // test function definition.
 void test(){
    printf(\"speeding violation fine for speed %d in %d mph zone(construction = %c) $%d.00\ \",35,45,\'y\',speeding(45,35,\'y\'));// calling speeding function and printing
    printf(\"speeding violation fine for speed %d in %d mph zone(construction = %c) $%d.00\ \",55,45,\'y\',speeding(45,55,\'y\'));
    printf(\"speeding violation fine for speed %d in %d mph zone(construction = %c) $%d.00\ \",55,45,\'n\',speeding(45,55,\'n\'));
    printf(\"speeding violation fine for speed %d in %d mph zone(construction = %c) $%d.00\ \",95,45,\'y\',speeding(45,95,\'y\'));
    printf(\"speeding violation fine for speed %d in %d mph zone(construction = %c) $%d.00\ \",95,45,\'n\',speeding(45,95,\'n\'));
    printf(\"speeding violation fine for speed %d in %d mph zone(construction = %c) $%d.00\ \",95,80,\'n\',speeding(80,95,\'n\'));
 }
// end of prgram
// please comment your response. it helps me to provide any additional information you needed.


