An ideal gas 1 atm and 20 degrees Celsius one mole occupies

An ideal gas, 1 atm and 20 degrees Celsius, one mole occupies 24.7 liters (+/-5%)?

Solution

sol:

we know that for ideal gas

PV = nRT

here P= 1 atm= 101325 Pa

n= 1 mol

R = 8.314 J/k.mol

T = 20 oC = 293 K

v = (nRT)/P

v = (1*8.314*298)/101325

v = 0.0244517 m^3

but 1 m3 = 1000L

v = 0.0244517 m^3 = 24.45 Lt