A box contains 100 pieces of jewelry Each piece is either a
A box contains 100 pieces of jewelry. Each piece is either a necklace or a ring with
equal probabilities. The price of each ring is a continuous uniform random variable in the interval
(0,9) and the price of each necklace is also a continuous uniform random variable in the interval
(0, 3).
(a) Let X be the price of a randomly chosen piece of jewelry from the box. Find the expectation
and the variance of X.
(b) If S is the total price of all pieces in the box, use the Central Limit Theorem to estimate the
probability that S is less than 300 + 10square root 6
Solution
P(ring) = 0.5
P(necklace) = 0.5
x price of ring is uniform in (0,3) and y is uniform in (0,9)
E(x) = Mean of uniform = 1.5
Var(x) = 9/12 = 0.75
b) Total prices of all pieces = 50x+50y=z
E(Z) = 50(1.5)+50(4.5)
= 300
Var(z) = 2500 (varx+vary)
= 2500(0.75 + 6.67)
= 18550
std error = 136.198
Prob for S < 300+10sq rt 6 = 1-1/6 = 5/6
