A mineshaft is 500 ft deep A chain that runs the length of t
A mineshaft is 500 ft deep. A chain that runs the length of the mineshaft is attached to a bucket filled with 200,000 lbs of coal. If the chain is 500 ft long and weighs 4000 lbs, then find the amount of work needed to bring the bucket to the top of the mine.
Solution
Work done = Change in potential energy let us asssume p.e. at top of mine as zero so, change = potential enrgy at bottom = work done so, work = m*g*h = 204000 * 32 * 500 (g = 32 ft/sec^2) = 3264 * 10^6 foot-pound force