Find the area of the AAS triangle ABC c 168 cm B 52 degree

Find the area of the AAS triangle ABC. c = 16.8 cm, B = 52 degree, C = 38.8degree the area of the triangle is about sq. cm. (Type an integer or decimal rounded to the nearest tenth as needed.)

Solution

Using sine rule :

b/sinB = c/sinC

b/sin52 = 16.8/sin(38.8)

b = 21.1275 cm

Now, we have angle A = 180 - 52 - 38.8 ----> A = 89.2

And now, area of the triangle is :

1/2 * b * c * sinA

1/2 * 21.1275 * 16.8 * sin(89.2)

177.5 sq cm ----> ANSWER