Assuming the value of rax is 0xb0 what is the value stored i

Assuming the value of %rax is 0xb0, what is the value stored in %rdx after the execution of the following statement:
leaq 8(%rax), %rdx
Give your answer in hex and omit a leading 0x

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Assuming the value of %rax is 0xb0 and the value of %rcx is 0xa00, what is the value stored in %rdx after the execution of the following statement:
leaq 8(%rax, %rcx), %rdx
Give your answer in hex and omit a leading 0x

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Assuming the value of %rax is 0xb0 and the value of %rcx is 0xf, what is the value stored in %rdx after the execution of the following statement:
leaq (%rax, %rcx, 2), %rdx
Give your answer in hex and omit a leading 0x

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Assuming the value of %rcx is 0x3, what is the value stored in %rdx after the execution of the following statement:
leaq (, %rcx, 4), %rdx
Give your answer in hex and omit a leading 0x

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Assuming the value of %rax is 0xf000 and the value of %rcx is 0x10, what is the value stored in %rdx after the execution of the following statement:
leaq 8(%rax, %rcx, 4), %rdx
Give your answer in hex and omit a leading 0x

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Using the values in memory and registers above, what is the destination address of the instruction below and the value that would be stored at that destination?

sarq $2, (%rax)

Select one:

a. destination address: 0x108, value: 0x04

b. destination address: 0x108, value: 0x18

c. destination address: 0x100, value: 0x10

d. destination address: 0x110, value: 0x03

e. destination address: 0x108, value: 0x12

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Using the values in memory and registers above, what is the destination address of the instruction below and the value that would be stored at that destination?

addq %rcx, (%rax)

Select one:

a. destination address: 0x100, value: 0x10

b. destination address: 0x118, value: 0x18

c. destination address: 0x108, value: 0x04

d. destination address: 0x118, value: 0x03

e. destination address: 0x108, value: 0x12

Question 8

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Using the values in memory and registers above, what is the destination address of the instruction below and the value that would be stored at that destination?

incq 8(%rax)

Select one:

a. destination address: 0x108, value: 0x18

b. destination address: 0x108, value: 0x04

c. destination address: 0x108, value: 0x12

d. destination address: 0x110, value: 0x0D

e. destination address: 0x100, value: 0x10

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Using the values in memory and registers above, what is the destination address of the instruction below and the value that would be stored at that destination?

imulq $2, (%rax, %rdx, 8)

Select one:

a. destination address: 0x100, value: 0x03

b. destination address: 0x100, value: 0x10

c. destination address: 0x110, value: 0xD0

d. destination address: 0x110, value: 0x18

e. destination address: 0x108, value: 0x04

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The code below was generated by the compiler of a C function named foo with the following prototype:

long foo(long a, long b);

The b parameter is in register %rdi and the a parameter is in register %rsi. The return value is placed in %rax.

_foo:                                  

shlq    $2, %rdi
addq    %rdi, %rsi
movq    %rsi, %rax
retq

What is returned if the function is called like this: foo(1, 2)

Give your answer in decimal.

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The code below was generated by the compiler of a C function named foo with the following prototype:

long foo(long a, long b);

The b parameter is in register %rdi and the a parameter is in register %rsi. The return value is placed in %rax.

_foo:                                  

shlq    $2, %rdi
addq    %rdi, %rsi
movq    %rsi, %rax
retq

What is returned if the function is called like this: foo(2, 4)

Give your answer in decimal.

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The code below was generated by the compiler of a C function named foo with the following prototype:

long foo(long a, long b);

The b parameter is in register %rdi and the a parameter is in register %rsi. The return value is placed in %rax.

_foo:                                  

shlq    $2, %rdi
addq    %rdi, %rsi
movq    %rsi, %rax
retq

What is returned if the function is called like this: foo(4, 1)

Give your answer in decimal.

Answer:

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The assembly code below was generated by a C compiler for a function with the following prototype:

long foo(long a, long b);

The register %rdi holds the parameter a and the register %rsi holds the parameter b. The result is returned in register %rax.

_foo:                 
movq   %rdi, %rax
cqto
idivq %rsi
retq

What is returned if foo is called like this: foo(5, 3)

Give your answer in decimal.

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The assembly code below was generated by a C compiler for a function with the following prototype:

long foo(long a, long b);

The register %rdi holds the parameter a and the register %rsi holds the parameter b. The result is returned in register %rax.

_foo:                 
movq   %rdi, %rax
cqto
idivq %rsi
retq

What is returned if foo is called like this: foo(2, 4)

Give your answer in decimal.

Answer:

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The assembly code below was generated by a C compiler for a function with the following prototype:

long foo(long a, long b);

The register %rdi holds the parameter a and the register %rsi holds the parameter b. The result is returned in register %rax.

_foo:                 
movq   %rdi, %rax
cqto
idivq %rsi
retq

What is returned if foo is called like this: foo(14, 2)

Give your answer in decimal.

Answer:

Address	Value		Register	Value
0x100	0xAB		%rax	0x108
0x108	0x10		%rdx	0x1
0x110	0x0C		%rcx	0x2
0x118	0x02

Solution

Answer1: leaq 8(%rax), %rdx after execution b8 get stored in %rdx

Because this instruction means take the value in %rax ,add 8 into that and then store the value in %rdx   

%rax=0xb0=176

0x8=8

176+8=184 and it will store in %rdx in hexa decimal=b8