The current going through a 1K resistor is it 2ut 1 4ut

The current going through a 1K resistor is i(t) = -2u(t + 1) + 4u(t) - 2u(t - 1) Find the energy delivered to the resistor

Solution

Well, power is really measuring the amount of energy consumed or delivered per unit time [ Watts = Joules/second]. Positive power means that the energy is being dissipated and negative power means that it is being delivered or sourced. If you attach two sides of a resistor with wires and connect it to a battery and make a closed loop circuit, what happens is that the electrical potential energy of the battery (voltage = Joules/Coulomb) — which is a measure of the energy required for a unit charge to jump across the gap between the positive and negative terminals of the battery — will cause an electrical current to flow because the electric field produced from the positive charges and pointing towards the negative charges attracts electrons from the negative terminal towards the positive terminal. When these electrons are impeded by the resistor, they bump into the resistor’s molecules and lose some energy which manifests itself as heat in the macroscopic world. That energy loss across the resistor is given by P = I^2*R which means that the amount of current flow is a more important factor in how much energy is lost, because I is squared.

Written May 22 · View Upvotes