What must be ones speed relative to a frame S in order that

What must be one\'s speed, relative to a frame S, in order that one\'s clocks will lose 1 second per day as observed from S? 1 minute per day as observed from S?

Solution

consider\' v \' be the speed ,relative to frame S, in order that one\'s

clocks will lose 1 sec/day asobserved from S. So,    

             t_o / t_p  = 24*60*60 day /s   

then,
                            t_o / t _p =  1 / [1 - (v / c )² ]

               [1- (v / c ) ² ] = t_p / t _o   
                                  v = 0.9999c    

consider \' v \' be the speed , relative to frameS, in order that

one\'s clocks will lose 1 min /day asobserved from S. thus,

           t_o / t_p  = 24*60 = day/minute   

then,
                             t_o / t _p =  1 / [1 - (v / c )² ]

                [1- (v / c ) ² ] = t_p / t _o   
                           (v/ c ) ²     = 1 -0.000694444         
                                      v   =   (0.999653)c