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Bar AB has a mass of 5 kg and the bar BC has a mass of 3 kg. The system is released from rest at the indicated configuration. What is the angular velocity of the bar AB, and the bar BC right before the bar BC falls flat on the smooth floor? 4. 1 m 2 m im-

Solution

Angular velocity for BC : theta = s/r = 1m/1m = 1 radian

Note: (Here the angle is made between smooth surface and point C and using simple sector geometry the above result is obtained)

W.K.T
s=(0.5)gt^2

Given, s=1m, choose g approx= 10m/s^2

t=0.44 sec

Angular velocity for AB : theta = s/t = 2m/0.44 sec =4.47m/sec.