i want complete answers step by step Details pipe Diameterm

Solution

Given: d = 225 mm = 0.225 m, h = 14 m, L = 15600 m,

Q = 92000 barrels/day = 0.127 m³/s

The crude oil at 20^oC has following properties

= 855 Kg/m³ and = 7.5*10^-3 N-s/m²

Let us first determine the average velocity required using

V = V_avg = Q/ A = 0.127/(d²/4)

                = 0.127 / (*0.225²/4)

= 3.194 m/s

Now Reynolds number is,

R_e = (*V_avg*d)/ = (855*3.194*0.225)/ 7.5*10^-3 = 81926.1 which is greater than 4000.

Therefore, flow is turbulent

As the material is galvanized iron, Using table 8.2 (FM by Cengel & Boles, page 368)

Roughness, = 0.15,

and / d = 0.15/ 225 = 0.00067,

thus for the using moody charts, friction factor,

f = 0.0340

(3) Now pressure drop, P = P_L = (fLV²)/ 2d = (0.0340*15600*855*3.194²)/ 2*0.225

= 10.28 *10⁶ N/m² = 10.28 MPa

Head loss, h_L = P_L / (g) = (10.28 *10⁶) / (855*9.81) = 1.048 m

(4)Pumping power required,

W = Q* P = (0.127)*(10.28*10⁶) = 1.306 MW