Homework SourseDetermine the magnitude 8 direction of the FRSolutionthe net
[Determine the magnitude 8 direction of the FR?
Solution
the net force along the x-direction:
Fx = 200*cos10 +400*sin30 = 396.96
the net force along the y-direction:
Fy = - 200*sin10 +400*cos30 = 311.68
magnitude: F = sqrt[Fx^2 + Fy^2] = 504.7 N
Direction: @ = tan-1[311.68 / 396.96] = 38.13o
