Homework SourseA survey on college students revealed that 23 are younger th
A survey on college students revealed that 23% are younger than 19 years of age. What is the probability that the number of Subway sandwich taker as their lunch in a random sample of 100 individuals will exceed 25? (Without Continuity Corrections)
Solution
P(X>25 ) = 0.2717
| x | p(x) |
| 1 | 0.0000 |
| 2 | 0.0000 |
| 3 | 0.0000 |
| 4 | 0.0000 |
| 5 | 0.0000 |
| 6 | 0.0000 |
| 7 | 0.0000 |
| 8 | 0.0001 |
| 9 | 0.0002 |
| 10 | 0.0004 |
| 11 | 0.0011 |
| 12 | 0.0024 |
| 13 | 0.0048 |
| 14 | 0.0089 |
| 15 | 0.0152 |
| 16 | 0.0241 |
| 17 | 0.0356 |
| 18 | 0.0490 |
| 19 | 0.0631 |
| 20 | 0.0764 |
| 21 | 0.0869 |
| 22 | 0.0932 |
| 23 | 0.0944 |
| 24 | 0.0905 |
| 25 | 0.0822 |
| 26 | 0.0708 |
| 27 | 0.0580 |
| 28 | 0.0451 |
| 29 | 0.0335 |
| 30 | 0.0237 |
| 31 | 0.0160 |
| 32 | 0.0103 |
| 33 | 0.0063 |
| 34 | 0.0037 |
| 35 | 0.0021 |
| 36 | 0.0011 |
| 37 | 0.0006 |
| 38 | 0.0003 |
| 39 | 0.0001 |
| 40 | 0.0001 |
| 41 | 0.0000 |
| 42 | 0.0000 |
| 43 | 0.0000 |
| 44 | 0.0000 |
| 45 | 0.0000 |
| 46 | 0.0000 |
| 47 | 0.0000 |
| 48 | 0.0000 |
| 49 | 0.0000 |
| 50 | 0.0000 |
| 51 | 0.0000 |
| 52 | 0.0000 |
| 53 | 0.0000 |
| 54 | 0.0000 |
| 55 | 0.0000 |
| 56 | 0.0000 |
| 57 | 0.0000 |
| 58 | 0.0000 |
| 59 | 0.0000 |
| 60 | 0.0000 |
| 61 | 0.0000 |
| 62 | 0.0000 |
| 63 | 0.0000 |
| 64 | 0.0000 |
| 65 | 0.0000 |
| 66 | 0.0000 |
| 67 | 0.0000 |
| 68 | 0.0000 |
| 69 | 0.0000 |
| 70 | 0.0000 |
| 71 | 0.0000 |
| 72 | 0.0000 |
| 73 | 0.0000 |
| 74 | 0.0000 |
| 75 | 0.0000 |
| 76 | 0.0000 |
| 77 | 0.0000 |
| 78 | 0.0000 |
| 79 | 0.0000 |
| 80 | 0.0000 |
| 81 | 0.0000 |
| 82 | 0.0000 |
| 83 | 0.0000 |
| 84 | 0.0000 |
| 85 | 0.0000 |
| 86 | 0.0000 |
| 87 | 0.0000 |
| 88 | 0.0000 |
| 89 | 0.0000 |
| 90 | 0.0000 |
| 91 | 0.0000 |
| 92 | 0.0000 |
| 93 | 0.0000 |
| 94 | 0.0000 |
| 95 | 0.0000 |
| 96 | 0.0000 |
| 97 | 0.0000 |
| 98 | 0.0000 |
| 99 | 0.0000 |
| 100 | 0.0000 |
