Two cyclists 64 miles apart start riding toward each other a

Two cyclists, 64 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?

Solution

Let speed of one cyclist be x mph

speed of other cyclist = 3x mph

They meet after 2 hrs

distance d1 = 2x

distance d2 = 3x* 2= 6x

Total distance = 2x +6x = 8x

8x = 64

x = 64/8 = 8 mph

faster cuclist = 3x = 24 mph