use substition to solve the system of linear equation xy2z8

use substition to solve the system of linear equation

x+y-2z=-8

-3+z=7

z=4

Solution

x+y-2z=-8

-3y+z=7

z=4

substituting the value of z that is 4 in second equation,we get

-3y+4=7

y=-1

Substituting the values of y and z in first equation

x-1-2(4)=-8

x-1=0

x=1

Therefore the answer is x=1,y=-1 and z=4