The 4kg block A has an initial speed of 5 ms as it slides do

The 4-kg block A has an initial speed of 5 m/s as it slides down the smooth ramp, after which it collides with the stationary block B of mass 9 kg. If the two blocks couple together after collision, determine their common velocity immediately after collision.

Solution

sol:

At bottom 1/2(mv²⁾ = (1/2)m*5² + mg(1.5)

so v = 7.38 m/s

Now use conservation of momentum 5 (7.38) = (5+9) V_final

V_final = 2.63 m/s