Please show full work step by step Answer is d 153 mV Sectio

Please show full work step by step. Answer is d) +153 mV

Sectioni. Multiple Choice: Circle the best answer. Refer to the mammalian cell shown below to answer questions l to 2: a 120 mM 140 mM A. 0 mM Cl- 2 mM 135 mM Nat 5 mM Cat* .00002 mM 135 mM Cat 2 mM K+ a 5 mM Goldman: vm RTF in ypcation leationlesutside tynAnion lanionlinsi Spcation [cation] inside SpAnion [anion]outside 1.987cal/mol- T is at 370C and F 23.062 calyV-mol

Solution

1. E_x = (RT/zF) ln ((x)_outside / (x) _inside)

R = 1.987 cal/mol

T = 37⁰ c = 37 + 273 = 310 k

F = faraday constant = 23,062

E_x = (RT/zF) ln ((x)_outside / (x) _inside)

= 1.987 x 300 / 23,062 log ₁₀ 28 7/ 267 (since ln = log ₁₀)

= 596 / 23,062 log ₁₀ (287/ 267)

2. Vm = RT/F ln ((cation ouside) + (anion inside)) / ((cation inside) + anion ouside))

= 1.987x 300 / 23,062 log ₁₀ (147 + 147) / (137 + 120)

= 1.987x 300 / 23,062 log ₁₀ ( 294) / 257)

= 596 / 23,062 log ₁₀ (294 / 257)