I dont need the work shown I just need the answers in the

In the figure below, a small block of mass m 0.017 kg can slide along the frictionless loop-the-loop, with loop radius R 11 cm. The block is released from rest at point P, at height h 5.4 above the bottom of the loop. R (a) How much work does the gravitational force do on the block as the block travels from point P to point Q? (b) How much work does the gravitational force do on the block as the block travels from point p to the top of the loop? If the gravitational potential energy of the block-Earth system is taken to be zero at the bottom of the loop, find the following. (c) the potential energy when the block is at point P (d) the potential energy when the block is at point Q (e) the potential energy when the block is at the top of the loop

Solution

Hieght covered by mass is,

h\'=5.4R-R

=4.4R

a)

W=mgh\'

=(0.017kg)(9.8 m/s²)4.4(0.11m)

=0.0806 J

b)

W=mgh\'\'

h\'\'=5.4R-2R

=3.4R

W=(0.017kg)(9.8 m/s²)3.4(0.11m)

=0.0623 J

c)

Potential energy of block at P

P.E=mgh

h=5.4R

P.E=(0.017kg)(9.8) 5.4(0.11m)

=0.0989 J

d)

At Q

PE=mgR

=0.0183 J

e)

At top

PE=mg2R

=0.0366 J