Find voltage across 2 Ohm and the average power dissipated i

Find voltage across 2 Ohm and the average power dissipated in the 2 Ohm resistor

Solution

Secondary voltage of first transformer V_s1=(N_s1/N_p1)*V_p1=(5/1)*120=600 V(rms)

Now this voltage becomes primary voltage for second transformer.

Secondary voltage of first transformer V_s2=(N_s2/N_p2)*V_p2=(1/4)*600=150 V(rms)

So voltage across 2 ohm resistor=150 V(rms)

Average power dissipated in the 2 ohm resistor=(V_s2*I_s2)/2=(150*75)/2=5625 A