113 There are three bridges connecting two towns A and B Bet
Solution
(a)
Salesperson can travel from A to B in three ways and from B to C in 4 ways. Since path from A to B and from B to C are independent from each other. So the possible number of choices of bridges from A to C is
3*4=12
So required number of ways is 12.
(b).
Salesperson can travel from A to B in three ways and from B to C in 4 ways, then again from C to B in 4 ways and then from B to A in three ways. Since path from A to B and from B to C are independent from each other. So the possible number of choices of bridges for a round-trip travel from A to C is
3*4*4*3=144
So required number of ways is 144.
(c)
Salesperson can travel from A to B in three ways and from B to C in 4 ways, then again from C to B in 3 ways (leaving the used bridge when saleperson travel from B to C) and then from B to A in 2 ways (leaving the used bridge when saleperson travel from A to B). Since path from A to B and from B to C are independent from each other. So the possible number of choices of bridges for a round-trip travel from A to C, if no bridge is repeated, is
3*4*3*2=72
So required number of ways is 72.
