A golfer hits a golfball with an initial velocity of 40 ms a

A golfer hits a golf-ball with an initial velocity of 40 m/s at an angle of 35degree from the horizontal. The horizontal velocity is ______ m/s and the vertical velocity is _______ m/s.

Solution

Solution:

Okay, to help you understand this, begin by drawing a right angled triangle, where the hypotenuse is 40 m/s and the angle (is the angle between the hypotenuse and the horizontal component. Let = 35°.

Then using trigonometry, find the vertical component of velocity (OPPOSITE) and the horizontal component of velocity (ADJACENT)

u(y) = 40sin35 = 22.94 m/s
u(x) = 40cos35 = 32.76 m/s