find the equation of the line through the point 6 1 and perp
find the equation of the line through the point (6, -1) and perpendicular to the graph of the line -3x+2y=14. write the equation in slope intercept form
Solution
To do this, you should follow this 4 steps:
Step 1: find the negative reciprocal of the slope:
slope = -3 ---> negative reciprocal = 1/3
Step 2: Plug the x and y given in the question into the slope intercept formula
-1 = 1/3(6) + b
Step 3: Solve for b
-1 = 6/3 + b
-1-2 = b
b = -3
Step 4: Substitute b into slope intercept equation
y = 1/3x - 3
Hope this helps
