the age of patients in an adult care facility averages 75 ye

the age of patients in an adult care facility averages 75 years old with a standard deviation of 5 years. if the distribution is considered approximately symmetrical and mound shaped, find the approximate 16th percentile of age distribution

Solution

First, we get the z score from the given left tailed area. As          
          
Left tailed area =    0.16      
          
Then, using table or technology,          
          
z =    -0.994457883      
          
As x = u + z * s,          
          
where          
          
u = mean =    75      
z = the critical z score =    -0.994457883      
s = standard deviation =    5      
          
Then          
          
x = critical value =    70.02771058   [ANSWER]