ASU ID 1206673345 ASU ID 1206673345 Plot the discrete time s

ASU ID 1206673345?

ASU ID 1206673345

Plot the discrete time signals, x_1[n] = {1, n = -2, 0, 1, 3, 5 2, n = -1, 2, 4, 6 and 0, elsewhere x_2[n] = u[n + 3] - u[n - 2] in MATLAB with proper axes labels. b. Plot the discrete time signal, h_1[n] = x_2[n - beta] in MATLAB with proper axes labels, where \'beta\' is given as the last digit of your ASU ID. c. Determine y_1[n] = x_1[n]*h_1[n] using the \'conv\' function in MATLAB. Plot y_1[n] with proper axes labels.

Solution

x1 = [1,2,1,1,2,1,2,1,2];
t1 = [-2:6];
subplot(4,1,1);
stem(t1,x1);
xlabel(\'X1\')
ylabel(\'time\')

x2 = [1,1,1,1,1];
t2 = [-3:1];
subplot(4,1,2);
stem(t2,x2);
xlabel(\'X2\');
ylabel(\'time\');

%last digit is 5
t3 = [2:6];
subplot(4,1,3);
stem(t3,x2);
xlabel(\'h1 = x2(n-B)\');
ylabel(\'time\');

%we need to reformat x2 and h1 to convolution with same length
x2 = [1,1,1,1,1,0,0,0,0,0];
h1 = [0,0,0,0,0,1,1,1,1,1];
y1 = conv(x2,h1);
ty = -3:15;
subplot(4,1,4);
stem(ty,y1);
xlabel(\'x2*h1\');
ylabel(\'time\');

ASU ID 1206673345? ASU ID 1206673345 Plot the discrete time signals, x_1[n] = {1, n = -2, 0, 1, 3, 5 2, n = -1, 2, 4, 6 and 0, elsewhere x_2[n] = u[n + 3] - u[n

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