2 An onthejob injury occurs every 8 days on average at an au

2. An on-the-job injury occurs every 8 days on average at an automobile plant. What is the probability that the next on-the-job injury will occur within

a. 10 days

b. 5 days

c. 1 day

Solution

This is a problem in exponential distribution, where ? = 0.10 per day and X = 7 days. So the probability is P(Next injury > 7 days) = exp(-0.10*(7)) = 0.4965