Chemical Engineering Question The process below is part of a

Chemical Engineering Question:

The process below is part of a system that liquefies carbon dioxide (all streams are CO₂). Stream 1 is at 20 degree C, 38 bar, passes through the heat exchanger where it becomes saturated liquid (stream 2) and is then throttled to 8 bar (stream 3) to produce a vapor-liquid mixture. Stream 3 is separated in a vapor/liquid separator, with all vapor exiting in stream 5 and all liquid as stream 4. Stream 6 is at 20 degree C, 38 bar and expands in a turbine. Stream 7, which contains 5% liquid, is mixed with stream 5. The resulting stream 8 is passed through the heat exchanger and exits at 20 degree C. Use the data given below and a basis of 1 mol/s in stream 1 to do the following:

a) Obtain the thermodynamic properties (T , P, H, S, phase) of all streams. If the state is vapor-liquid mixture, instead of phase report the liquid fraction.

b) Calculate all molar flow rates.

c) Calculate the work in the turbine.

d) Calculate the efficiency of the turbine.

e) Calculate the amount of heat that is exchanged between the two streams in the heat exchanger.

Summarize your results in the table below but you must show your work.

turbine exchanger VIL valve Data for CO2 T (PC) P (bar) H (kJ kg) S(kJ/kg K) Phase T (OC) P (bar) H (kJ/kg) S (kJ/kg K) Phase 0.0000 38 99.66 0.99753 liq -46.005 8 100.87 0.61414 sat liq 3.3047 38 208.19 1.0286 sat liq -46.005 8 433.86 2.0801 vapor 3.3047 38 428.76 1.8264. vapor 0.0000 8 476.57 2.2516 vapor 481.09 2.2679 vapor 485.60 2.2840 vapor 5.0000 38 432.10 1.8385 vapor 5.0000 8 10.000 38 441.02 1.8703 vapor 0.000 8 490.11 2.2998 vapor 15.000 38 449.00 1.8982 vapor 15.000 8 1.9235 vapor 20.000 8 456.37 494.62 2.3153 vapor 20.000 38 T (OC) P (bar) H (kJ/kg) S (kJ/kg K) phase kJ/s kJ/s eff

Solution

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