Two plates of area 400 Times 103 m2 are separated by a dista

Two plates of area 4.00 Times 10^-3 m^2 are separated by a distance of 3.70 Times 10^-4 m. If a charge of 3.40 Times 10^-8 C is moved from one plate to the other, calculate the potential difference (voltage) between the two plates. Assume that the separation distance is small in comparison to the diameter of the plates.

Solution

C = epsilon₀ A / d

= (8.85 * 10^-12 * 4 * 10^-3) / (3.7 * 10^-4) = 9.57 * 10^-11 F

V = Q / C = 3.4 * 10^-8 / ( 9.57 * 10^-11 )

= 355 V