Write a function that finds the number of occurrences of a s

Write a function that finds the number of occurrences of a specified character in a string using the following header:

def count(s, ch):

The str class has the count method. Implement your method without using the count method. For example, count(“system error, syntax error”, “error”) returns 2. Write a test program that prompts the user to enter two strings and displays the number of occurrences of the second string in the first string. Needs to be written in python 3 please.

Solution

Function to find substring in the given string is as follows. This funtion finds all overlapped occurrences.

def count(s,ch):
s = s.lower()
ch = ch.lower()
l = len(ch)
ct = 0
for c in range(0,len(s)):
if s[c:c+l] == ch:
ct += 1
print (\"\'\" + ch + \"\' occureed in \'\" + s + \"\' \" + str(ct) + \" times.\")

text = raw_input(\"Enter String: \")
pattern = raw_input(\"Enter petten to be search: \")
count(text,pattern)