A cylindrical rod of diameter 91 mm and fabricated from a re
A cylindrical rod of diameter 9.1 mm and fabricated from a red brass alloy is subjected to reversed tension-compression load cycling along it axis. If the maximum and minimum loads are +7850 N and -3860 N, respectively, determine its fatigue life (in cycles).
Solution
solution:
1) here cylindrical rod has material=red brass alloy and diameter d=9.1 mm
Sut=240 MPa
Syt=70 MPa
Nf=1
here rod subjected to fluctuating stress as mean stress not eual to zero
here Fmax=7850N
Fmin=-3860 N
2) here tensile and compressive stress are given as
max.stress=Fmax*4/(pi*d2)=120.697143 N/mm2
min.stress=Fmin*4/(pi*d2)=-59.3491 N/mm2
3) here mean stress
mean stress=(max.stress+min stress)/2=120.697-59.34/2=30.6739 N/mm2
4) amplitude stress
amplitude stress=(max.stress-min.stress)/2=120.697+59.34/2=90.02 N/mm2
5) here to convert it to completely reversed stress fatigue stress acting is given by
fatigue stress=Sut*(amplitude stress/(Sut-mean stress)=240(90.02/(240-30.67))=103.2148 N/mm2
here fatigue strength isSxf=fatigue stress*Nf=103.2148 N/mm2
6) here by goodman line we get
logSxf-logSe/(6-logNxf)=log(.9Sut-logse)/6-3
on putting value we get fatigue finite life as
Nxf=5875596.011 cycle
