The angle of elevation of a pedestrian crosswalk over a busy

The angle of elevation of a pedestrian crosswalk over a busy highway is B33\", as shownin the drawing the distance between ends ofte orosswak measured on the groundis30 m. nenwhat is the orosswak at heighthoftheo The height h of the crosswalk at the enter is

Solution

Since the base angles are same which is 8.33 degree,so its an isosceles triangle. And in isosceles triangle the altitude divides the base in two equal parts

Therefore in this question each part is equal to 170 feet

tan 8.33=h/170

h=170 tan 8.33

h= 24.9 feet

Therefore the height at the centre is 24.9 feet